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/ \[ \frac{2x + 4}{x^2 + 4x + 5} = 0 \]
\[ \frac{2x + 4}{x^2 + 4x + 5} = 0 \]
February 22, 2026
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Differentiate \( R(x) \):
\[ R'(x) = \frac{d}{dx}[\ln(x^2 + 4x + 5)] = \frac{2x + 4}{x^2 + 4x + 5} \]
Set the derivative to zero:
The numerator must be zero, so:
\[ 2x + 4 = 0 \]
\[ x = -2 \]
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![\[ \frac{2x + 4}{x^2 + 4x + 5} = 0 \]](https://soloferat.biz.id/images/frac2x--4x2--4x--5--0-.jpg)
