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Now evaluate $g(f(2)) = g(3)$:g(3) = \sqrt{3 + 4} = \sqrt{7}oxed{\sqrt{7}}Question: If $x + rac{1}{x} = 4$, what is the value of $x^2 + rac{1}{x^2}$?Solution: Start with the identity:\left(x + rac{1}{x}ight)^2 = x^2 + 2 + rac{1}{x^2}Substitute $x + rac{1}{x} = 4$:4^2 = x^2 + 2 + rac{1}{x^2} \Rightarrow 16 = x^2 + rac{1}{x^2} + 2Solve for $x^2 + rac{1}{x^2}$: